Partial derivative of ( (5x^2)/ ( (x^2y^2))) full pad » x^2 x^ {\msquare} \log_ {\msquare} \sqrt {\square} \nthroot \msquare {\square} \le \ge It depends on whether we need d/dx or d/dt For d/dt d/dt(ln(x^2y^2)) = 1/(x^2y^2) d/dt(x^2y^2) = 1/(x^2y^2) * (2xdx/dt 2y dy/dt) For d/dx d/dx(ln(x^2y^2)) = 1/(x^2y^2) d/dx(x^2y^2) = 1/(x^2y^2) * (2x 2y dy/dx)Differentiate using the Power Rule which states that d d x x n d d x x n is n x n − 1 n x n 1 where n = 2 n = 2 Since y 2 y 2 is constant with respect to x x, the derivative of y 2 y 2 with respect to x x is 0 0 Combine fractions Tap for more steps Add 2 x 2 x and 0 0 Combine 2 2 and 1 x 2 y 2 1 x 2 y 2
If Logsqrt X 2 Y 2 Tan 1 Y X Then Dy Dx Is
